Fortran file open error




















Sorry, you must verify to complete this action. Please click the verification link in your email. You may re-send via your profile. I'm simply trying to compile and build a set of existing Fortran subroutines. I add the existing. These routines have many includes. Regardless of where I add the. View solution in original post. I have the similar problem. If the file name is not specified, a default name is created. If you open a unit that is already open without specifying a file name or with the previous file name , FORTRAN thinks you are reopening the file to change parameters.

The file position is not changed. To change any other parameters, you must close, then reopen the file. If you open a unit that is already open, but you specify a different file name, it is as if you closed with the old file name before the open. If you open a file that is already open, but you specify a different unit, that is an error. This is for opening a file to append records to an existing sequential-access file.

This is an extension and can be applied only to disk files. Only directly accessible files are allowed; thus, tty, pipes, and magnetic tape are not allowed. If you build a file as sequential, then you cannot access it as direct. Files do not have to be randomly accessible, in the sense that tty, pipes, and tapes can be used. If -xl[d] is not set, rl is number of characters, and record length is rl. The default buffer size for tape is 64K characters. After the execution of the OPEN , if no error condition exists, then ios is zero; otherwise, it is some positive number.

Add a comment. Active Oldest Votes. Two things: 1 Please stop using unit numbers less than Improve this answer. Thank you for reminding me.

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